Base | Representation |
---|---|
bin | 10000110110011111100010… |
… | …110101101111011010101011 |
3 | 100201102011210220102101200121 |
4 | 100312133202311233122223 |
5 | 34203233334401244042 |
6 | 421343131220544111 |
7 | 21416343534264643 |
oct | 2066374265573253 |
9 | 321364726371617 |
10 | 74113466431147 |
11 | 21684387736930 |
12 | 838b829b52037 |
13 | 3247b40214410 |
14 | 144317a4c9523 |
15 | 887cdc074367 |
hex | 4367e2d6f6ab |
74113466431147 has 32 divisors (see below), whose sum is σ = 88499718530496. Its totient is φ = 61172198092800.
The previous prime is 74113466431099. The next prime is 74113466431163.
74113466431147 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 74113466431147 - 211 = 74113466429099 is a prime.
It is a Smith number, since the sum of its digits (52) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a junction number, because it is equal to n+sod(n) for n = 74113466431094 and 74113466431103.
It is not an unprimeable number, because it can be changed into a prime (74113466431847) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 641545063 + ... + 641660575.
It is an arithmetic number, because the mean of its divisors is an integer number (2765616204078).
Almost surely, 274113466431147 is an apocalyptic number.
74113466431147 is a deficient number, since it is larger than the sum of its proper divisors (14386252099349).
74113466431147 is a wasteful number, since it uses less digits than its factorization.
74113466431147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189151.
The product of its digits is 4064256, while the sum is 52.
The spelling of 74113466431147 in words is "seventy-four trillion, one hundred thirteen billion, four hundred sixty-six million, four hundred thirty-one thousand, one hundred forty-seven".
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