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74332312441 is a prime number
BaseRepresentation
bin100010100111010001…
…1010001001101111001
321002212100100201021221
41011032203101031321
52204213032444231
654051531232041
75241011142112
oct1051643211571
9232770321257
1074332312441
112958471a582
12124a58a8621
137017b6b53a
143852151209
151e00b28d11
hex114e8d1379

74332312441 has 2 divisors, whose sum is σ = 74332312442. Its totient is φ = 74332312440.

The previous prime is 74332312427. The next prime is 74332312459. The reversal of 74332312441 is 14421323347.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68494741225 + 5837571216 = 261715^2 + 76404^2 .

It is an emirp because it is prime and its reverse (14421323347) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 74332312441 - 25 = 74332312409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 74332312397 and 74332312406.

It is not a weakly prime, because it can be changed into another prime (74332312841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37166156220 + 37166156221.

It is an arithmetic number, because the mean of its divisors is an integer number (37166156221).

Almost surely, 274332312441 is an apocalyptic number.

It is an amenable number.

74332312441 is a deficient number, since it is larger than the sum of its proper divisors (1).

74332312441 is an equidigital number, since it uses as much as digits as its factorization.

74332312441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48384, while the sum is 34.

Adding to 74332312441 its reverse (14421323347), we get a palindrome (88753635788).

The spelling of 74332312441 in words is "seventy-four billion, three hundred thirty-two million, three hundred twelve thousand, four hundred forty-one".