Base | Representation |
---|---|
bin | 11010110111001001… |
… | …11110111001010011 |
3 | 1101020001021010112221 |
4 | 31123210332321103 |
5 | 214013324321342 |
6 | 10343003001511 |
7 | 1020242140324 |
oct | 153344767123 |
9 | 41201233487 |
10 | 14421323347 |
11 | 6130508752 |
12 | 2965809297 |
13 | 148a9a8032 |
14 | 9ab42c44b |
15 | 596109a67 |
hex | 35b93ee53 |
14421323347 has 2 divisors, whose sum is σ = 14421323348. Its totient is φ = 14421323346.
The previous prime is 14421323341. The next prime is 14421323381. The reversal of 14421323347 is 74332312441.
It is an a-pointer prime, because the next prime (14421323381) can be obtained adding 14421323347 to its sum of digits (34).
It is a weak prime.
It is an emirp because it is prime and its reverse (74332312441) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14421323347 - 215 = 14421290579 is a prime.
It is not a weakly prime, because it can be changed into another prime (14421323341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7210661673 + 7210661674.
It is an arithmetic number, because the mean of its divisors is an integer number (7210661674).
Almost surely, 214421323347 is an apocalyptic number.
14421323347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14421323347 is an equidigital number, since it uses as much as digits as its factorization.
14421323347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48384, while the sum is 34.
Adding to 14421323347 its reverse (74332312441), we get a palindrome (88753635788).
The spelling of 14421323347 in words is "fourteen billion, four hundred twenty-one million, three hundred twenty-three thousand, three hundred forty-seven".
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