Base | Representation |
---|---|
bin | 110110000101110010011… |
… | …1010101001010010100111 |
3 | 222022200210120200020202012 |
4 | 1230023210322221102213 |
5 | 1433300101301011212 |
6 | 23451105523504435 |
7 | 1365045525246443 |
oct | 154134472512247 |
9 | 28280716606665 |
10 | 7434134000807 |
11 | 2406886921768 |
12 | a0095052811b |
13 | 41c060939c87 |
14 | 1b9b578b9823 |
15 | cd5a3b15922 |
hex | 6c2e4ea94a7 |
7434134000807 has 2 divisors, whose sum is σ = 7434134000808. Its totient is φ = 7434134000806.
The previous prime is 7434134000749. The next prime is 7434134000827. The reversal of 7434134000807 is 7080004314347.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7434134000807 - 28 = 7434134000551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7434134000827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3717067000403 + 3717067000404.
It is an arithmetic number, because the mean of its divisors is an integer number (3717067000404).
Almost surely, 27434134000807 is an apocalyptic number.
7434134000807 is a deficient number, since it is larger than the sum of its proper divisors (1).
7434134000807 is an equidigital number, since it uses as much as digits as its factorization.
7434134000807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 225792, while the sum is 41.
The spelling of 7434134000807 in words is "seven trillion, four hundred thirty-four billion, one hundred thirty-four million, eight hundred seven", and thus it is an aban number.
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