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75003055550041 is a prime number
BaseRepresentation
bin10001000011011100000010…
…011110111010111001011001
3100211120012222220021220212211
4101003130002132322321121
534312322224210100131
6423303532243035121
721540535431112303
oct2103340236727131
9324505886256784
1075003055550041
1121997687594653
1284b411766baa1
1332b09b0b31b38
14147424ad54973
158a10055d05b1
hex4437027bae59

75003055550041 has 2 divisors, whose sum is σ = 75003055550042. Its totient is φ = 75003055550040.

The previous prime is 75003055550029. The next prime is 75003055550069. The reversal of 75003055550041 is 14005555030057.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70277975174416 + 4725080375625 = 8383196^2 + 2173725^2 .

It is a cyclic number.

It is not a de Polignac number, because 75003055550041 - 27 = 75003055549913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 75003055549976 and 75003055550003.

It is not a weakly prime, because it can be changed into another prime (75003055551041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37501527775020 + 37501527775021.

It is an arithmetic number, because the mean of its divisors is an integer number (37501527775021).

Almost surely, 275003055550041 is an apocalyptic number.

It is an amenable number.

75003055550041 is a deficient number, since it is larger than the sum of its proper divisors (1).

75003055550041 is an equidigital number, since it uses as much as digits as its factorization.

75003055550041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 262500, while the sum is 40.

The spelling of 75003055550041 in words is "seventy-five trillion, three billion, fifty-five million, five hundred fifty thousand, forty-one".