Search a number
-
+
75132012047 = 591273423933
BaseRepresentation
bin100010111111000110…
…1111000011000001111
321011221002010122220212
41011332031320120033
52212332243341142
654303135433035
75266561364621
oct1057615703017
9234832118825
1075132012047
1129955075744
121268968577b
137114747781
1438ca43cc11
151e4ae41d82
hex117e37860f

75132012047 has 4 divisors (see below), whose sum is σ = 76405436040. Its totient is φ = 73858588056.

The previous prime is 75132012019. The next prime is 75132012097. The reversal of 75132012047 is 74021023157.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74021023157 = 383193266379.

It is a cyclic number.

It is not a de Polignac number, because 75132012047 - 28 = 75132011791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (75132012097) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 636711908 + ... + 636712025.

It is an arithmetic number, because the mean of its divisors is an integer number (19101359010).

Almost surely, 275132012047 is an apocalyptic number.

75132012047 is a deficient number, since it is larger than the sum of its proper divisors (1273423993).

75132012047 is a wasteful number, since it uses less digits than its factorization.

75132012047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1273423992.

The product of its (nonzero) digits is 11760, while the sum is 32.

It can be divided in two parts, 751320 and 12047, that added together give a palindrome (763367).

The spelling of 75132012047 in words is "seventy-five billion, one hundred thirty-two million, twelve thousand, forty-seven".

Divisors: 1 59 1273423933 75132012047