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7514499792013 is a prime number
BaseRepresentation
bin110110101011001101100…
…0101110011110010001101
3222121101020102002102221121
41231112123011303302031
51441104143421321023
623552040305400541
71403622211224634
oct155263305636215
928541212072847
107514499792013
112437977259125
12a1443a939151
134267ca796796
141bd9bd07251b
15d070928bd5d
hex6d59b173c8d

7514499792013 has 2 divisors, whose sum is σ = 7514499792014. Its totient is φ = 7514499792012.

The previous prime is 7514499791989. The next prime is 7514499792017. The reversal of 7514499792013 is 3102979944157.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4023125327529 + 3491374464484 = 2005773^2 + 1868522^2 .

It is a cyclic number.

It is not a de Polignac number, because 7514499792013 - 213 = 7514499783821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7514499792017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3757249896006 + 3757249896007.

It is an arithmetic number, because the mean of its divisors is an integer number (3757249896007).

Almost surely, 27514499792013 is an apocalyptic number.

It is an amenable number.

7514499792013 is a deficient number, since it is larger than the sum of its proper divisors (1).

7514499792013 is an equidigital number, since it uses as much as digits as its factorization.

7514499792013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17146080, while the sum is 61.

The spelling of 7514499792013 in words is "seven trillion, five hundred fourteen billion, four hundred ninety-nine million, seven hundred ninety-two thousand, thirteen".