7664125504001 has 2 divisors, whose sum is σ = 7664125504002. Its totient is φ = 7664125504000.

The previous prime is 7664125503961. The next prime is 7664125504003. The reversal of 7664125504001 is 1004055214667.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6055654758976 + 1608470745025 = 2460824^2 + 1268255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-7664125504001 is a prime.

It is a super-3 number, since 3×7664125504001³ (a number of 40 digits) contains 333 as substring.

Together with 7664125504003, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 7664125504001.

It is not a weakly prime, because it can be changed into another prime (7664125504003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3832062752000 + 3832062752001.

It is an arithmetic number, because the mean of its divisors is an integer number (3832062752001).

Almost surely, 2^{7664125504001} is an apocalyptic number.

It is an amenable number.

7664125504001 is a deficient number, since it is larger than the sum of its proper divisors (1).

7664125504001 is an equidigital number, since it uses as much as digits as its factorization.

7664125504001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 7664125504001 in words is "seven trillion, six hundred sixty-four billion, one hundred twenty-five million, five hundred four thousand, one".