Base | Representation |
---|---|
bin | 10001011100011110111001… |
… | …110001011101101100110001 |
3 | 101001122202100200002201021220 |
4 | 101130132321301131230301 |
5 | 40024021443043410423 |
6 | 431102323434535253 |
7 | 22106064104611122 |
oct | 2134367161355461 |
9 | 331582320081256 |
10 | 76724117560113 |
11 | 224a0574195031 |
12 | 8731793897529 |
13 | 33a708cc8125a |
14 | 14d3677a38049 |
15 | 8d0b84ee99e3 |
hex | 45c7b9c5db31 |
76724117560113 has 16 divisors (see below), whose sum is σ = 108484856053056. Its totient is φ = 48065753986560.
The previous prime is 76724117560063. The next prime is 76724117560121. The reversal of 76724117560113 is 31106571142767.
It is a de Polignac number, because none of the positive numbers 2k-76724117560113 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is not an unprimeable number, because it can be changed into a prime (76724117560133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1169791828 + ... + 1169857413.
It is an arithmetic number, because the mean of its divisors is an integer number (6780303503316).
Almost surely, 276724117560113 is an apocalyptic number.
It is an amenable number.
76724117560113 is a deficient number, since it is larger than the sum of its proper divisors (31760738492943).
76724117560113 is a wasteful number, since it uses less digits than its factorization.
76724117560113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2339649904.
The product of its (nonzero) digits is 1481760, while the sum is 51.
The spelling of 76724117560113 in words is "seventy-six trillion, seven hundred twenty-four billion, one hundred seventeen million, five hundred sixty thousand, one hundred thirteen".
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