Base | Representation |
---|---|
bin | 100100000100010101… |
… | …0110001100010001001 |
3 | 21101220221221122120121 |
4 | 1020020222301202021 |
5 | 2232111414420433 |
6 | 55325434023241 |
7 | 5411255202604 |
oct | 1101052614211 |
9 | 241827848517 |
10 | 77454841993 |
11 | 2a93726a211 |
12 | 13017577b21 |
13 | 73c4a54169 |
14 | 3a6ab3133b |
15 | 2034d22c2d |
hex | 1208ab1889 |
77454841993 has 2 divisors, whose sum is σ = 77454841994. Its totient is φ = 77454841992.
The previous prime is 77454841921. The next prime is 77454842011. The reversal of 77454841993 is 39914845477.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43853385744 + 33601456249 = 209412^2 + 183307^2 .
It is a cyclic number.
It is not a de Polignac number, because 77454841993 - 233 = 68864907401 is a prime.
It is not a weakly prime, because it can be changed into another prime (77454841903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38727420996 + 38727420997.
It is an arithmetic number, because the mean of its divisors is an integer number (38727420997).
Almost surely, 277454841993 is an apocalyptic number.
It is an amenable number.
77454841993 is a deficient number, since it is larger than the sum of its proper divisors (1).
77454841993 is an equidigital number, since it uses as much as digits as its factorization.
77454841993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 30481920, while the sum is 61.
It can be divided in two parts, 7745484 and 1993, that added together give a palindrome (7747477).
The spelling of 77454841993 in words is "seventy-seven billion, four hundred fifty-four million, eight hundred forty-one thousand, nine hundred ninety-three".
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