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79100639473 is a prime number
BaseRepresentation
bin100100110101011000…
…0111111100011110001
321120011122210211021211
41021222300333203301
52243444230430343
6100201025120121
75500121225152
oct1115260774361
9246148724254
1079100639473
1130601281219
12133b6789041
1375c7a0351b
143b85547929
1520ce56b79d
hex126ac3f8f1

79100639473 has 2 divisors, whose sum is σ = 79100639474. Its totient is φ = 79100639472.

The previous prime is 79100639363. The next prime is 79100639539. The reversal of 79100639473 is 37493600197.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43094438464 + 36006201009 = 207592^2 + 189753^2 .

It is an emirp because it is prime and its reverse (37493600197) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 79100639473 - 229 = 78563768561 is a prime.

It is a super-2 number, since 2×791006394732 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (79100639573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39550319736 + 39550319737.

It is an arithmetic number, because the mean of its divisors is an integer number (39550319737).

Almost surely, 279100639473 is an apocalyptic number.

It is an amenable number.

79100639473 is a deficient number, since it is larger than the sum of its proper divisors (1).

79100639473 is an equidigital number, since it uses as much as digits as its factorization.

79100639473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 857304, while the sum is 49.

The spelling of 79100639473 in words is "seventy-nine billion, one hundred million, six hundred thirty-nine thousand, four hundred seventy-three".