79115514343 has 4 divisors (see below), whose sum is σ = 79135644328. Its totient is φ = 79095384360.

The previous prime is 79115514329. The next prime is 79115514367. The reversal of 79115514343 is 34341551197.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34341551197 = 19 ⋅1807450063.

It is a cyclic number.

It is not a de Polignac number, because 79115514343 - 2⁹ = 79115513831 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 79115514343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (79115584343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10059096 + ... + 10066957.

It is an arithmetic number, because the mean of its divisors is an integer number (19783911082).

Almost surely, 2^79115514343 is an apocalyptic number.

79115514343 is a deficient number, since it is larger than the sum of its proper divisors (20129985).

79115514343 is a wasteful number, since it uses less digits than its factorization.

79115514343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20129984.

The product of its digits is 226800, while the sum is 43.

The spelling of 79115514343 in words is "seventy-nine billion, one hundred fifteen million, five hundred fourteen thousand, three hundred forty-three".