Base | Representation |
---|---|
bin | 111001110101010100100… |
… | …0001000111110101010011 |
3 | 1001010212112101100122111022 |
4 | 1303222221001013311103 |
5 | 2020212034414010311 |
6 | 24523300235110055 |
7 | 1450155601640045 |
oct | 163525101076523 |
9 | 31125471318438 |
10 | 7948525141331 |
11 | 2594a50252025 |
12 | a84588ba232b |
13 | 4587094257c8 |
14 | 1d69d4111a95 |
15 | dbb5cd905db |
hex | 73aa9047d53 |
7948525141331 has 4 divisors (see below), whose sum is σ = 8222612215200. Its totient is φ = 7674438067464.
The previous prime is 7948525141279. The next prime is 7948525141351. The reversal of 7948525141331 is 1331415258497.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-7948525141331 is a prime.
It is a super-2 number, since 2×79485251413312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (7948525141351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137043536891 + ... + 137043536948.
It is an arithmetic number, because the mean of its divisors is an integer number (2055653053800).
Almost surely, 27948525141331 is an apocalyptic number.
7948525141331 is a deficient number, since it is larger than the sum of its proper divisors (274087073869).
7948525141331 is a wasteful number, since it uses less digits than its factorization.
7948525141331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274087073868.
The product of its digits is 3628800, while the sum is 53.
The spelling of 7948525141331 in words is "seven trillion, nine hundred forty-eight billion, five hundred twenty-five million, one hundred forty-one thousand, three hundred thirty-one".
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