Base | Representation |
---|---|
bin | 100101010000000000… |
… | …0111001001100001111 |
3 | 21122110220211020202001 |
4 | 1022200000321030033 |
5 | 2302311431001033 |
6 | 100425421013131 |
7 | 5531216532211 |
oct | 1124000711417 |
9 | 248426736661 |
10 | 79994000143 |
11 | 30a1a589322 |
12 | 136059b41a7 |
13 | 770ab13bc5 |
14 | 3c2c0565b1 |
15 | 2132bd5e7d |
hex | 12a003930f |
79994000143 has 2 divisors, whose sum is σ = 79994000144. Its totient is φ = 79994000142.
The previous prime is 79994000087. The next prime is 79994000153. The reversal of 79994000143 is 34100049997.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 79994000143 - 225 = 79960445711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 79994000093 and 79994000102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (79994000153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39997000071 + 39997000072.
It is an arithmetic number, because the mean of its divisors is an integer number (39997000072).
Almost surely, 279994000143 is an apocalyptic number.
79994000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
79994000143 is an equidigital number, since it uses as much as digits as its factorization.
79994000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 244944, while the sum is 46.
The spelling of 79994000143 in words is "seventy-nine billion, nine hundred ninety-four million, one hundred forty-three", and thus it is an aban number.
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