Base | Representation |
---|---|
bin | 10111010100000010100… |
… | …10111100101001100111 |
3 | 2211120121101011221101212 |
4 | 23222001102330221213 |
5 | 101111003441114220 |
6 | 1411553424142035 |
7 | 111605230250252 |
oct | 13520122745147 |
9 | 2746541157355 |
10 | 801033144935 |
11 | 289797366891 |
12 | 10b2b446791b |
13 | 5a6ca02013a |
14 | 2aaad660099 |
15 | 15c83d6e0c5 |
hex | ba814bca67 |
801033144935 has 16 divisors (see below), whose sum is σ = 988515511200. Its totient is φ = 622886770176.
The previous prime is 801033144917. The next prime is 801033144991. The reversal of 801033144935 is 539441330108.
801033144935 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 801033144935 - 236 = 732313668199 is a prime.
It is a super-3 number, since 3×8010331449353 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 801033144892 and 801033144901.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15228614 + ... + 15281123.
It is an arithmetic number, because the mean of its divisors is an integer number (61782219450).
Almost surely, 2801033144935 is an apocalyptic number.
801033144935 is a deficient number, since it is larger than the sum of its proper divisors (187482366265).
801033144935 is a wasteful number, since it uses less digits than its factorization.
801033144935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30509890.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 801033144935 in words is "eight hundred one billion, thirty-three million, one hundred forty-four thousand, nine hundred thirty-five".
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