Base | Representation |
---|---|
bin | 100101011000000111… |
… | …0101101011001111111 |
3 | 21200011212202012001122 |
4 | 1022300032231121333 |
5 | 2303341102313333 |
6 | 100512420101155 |
7 | 5541032141663 |
oct | 1126016553177 |
9 | 250155665048 |
10 | 80266057343 |
11 | 3104a10798a |
12 | 13680b347bb |
13 | 77522aa1b4 |
14 | 3c562348a3 |
15 | 214ba25798 |
hex | 12b03ad67f |
80266057343 has 2 divisors, whose sum is σ = 80266057344. Its totient is φ = 80266057342.
The previous prime is 80266057309. The next prime is 80266057369. The reversal of 80266057343 is 34375066208.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80266057343 - 224 = 80249280127 is a prime.
It is a super-2 number, since 2×802660573432 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 80266057294 and 80266057303.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80266057373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40133028671 + 40133028672.
It is an arithmetic number, because the mean of its divisors is an integer number (40133028672).
Almost surely, 280266057343 is an apocalyptic number.
80266057343 is a deficient number, since it is larger than the sum of its proper divisors (1).
80266057343 is an equidigital number, since it uses as much as digits as its factorization.
80266057343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 44.
The spelling of 80266057343 in words is "eighty billion, two hundred sixty-six million, fifty-seven thousand, three hundred forty-three".
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