Base | Representation |
---|---|
bin | 100101011010010101… |
… | …0010100100000111001 |
3 | 21200101001122101212221 |
4 | 1022310222110200321 |
5 | 2304014120414111 |
6 | 100524033404041 |
7 | 5542624111624 |
oct | 1126452244071 |
9 | 250331571787 |
10 | 80340404281 |
11 | 31088077935 |
12 | 136a1a09621 |
13 | 776480b477 |
14 | 3c62068dbb |
15 | 215330e371 |
hex | 12b4a94839 |
80340404281 has 2 divisors, whose sum is σ = 80340404282. Its totient is φ = 80340404280.
The previous prime is 80340404273. The next prime is 80340404341. The reversal of 80340404281 is 18240404308.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42516378025 + 37824026256 = 206195^2 + 194484^2 .
It is a cyclic number.
It is not a de Polignac number, because 80340404281 - 23 = 80340404273 is a prime.
It is a super-2 number, since 2×803404042812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (80340404231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40170202140 + 40170202141.
It is an arithmetic number, because the mean of its divisors is an integer number (40170202141).
Almost surely, 280340404281 is an apocalyptic number.
It is an amenable number.
80340404281 is a deficient number, since it is larger than the sum of its proper divisors (1).
80340404281 is an equidigital number, since it uses as much as digits as its factorization.
80340404281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24576, while the sum is 34.
Adding to 80340404281 its reverse (18240404308), we get a palindrome (98580808589).
The spelling of 80340404281 in words is "eighty billion, three hundred forty million, four hundred four thousand, two hundred eighty-one".
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