Base | Representation |
---|---|
bin | 10010010010000000001001… |
… | …010010011001000000110111 |
3 | 101112200100110200122100121222 |
4 | 102102000021102121000313 |
5 | 41014301140030101421 |
6 | 443000050514500555 |
7 | 22635564054250253 |
oct | 2222001122310067 |
9 | 345610420570558 |
10 | 80401943597111 |
11 | 236893000a4844 |
12 | 902652829475b |
13 | 35b2b4205a006 |
14 | 15bd690d2d263 |
15 | 94668bca2cab |
hex | 492009499037 |
80401943597111 has 2 divisors, whose sum is σ = 80401943597112. Its totient is φ = 80401943597110.
The previous prime is 80401943597093. The next prime is 80401943597159. The reversal of 80401943597111 is 11179534910408.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 80401943597111 - 226 = 80401876488247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80401943597161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40200971798555 + 40200971798556.
It is an arithmetic number, because the mean of its divisors is an integer number (40200971798556).
Almost surely, 280401943597111 is an apocalyptic number.
80401943597111 is a deficient number, since it is larger than the sum of its proper divisors (1).
80401943597111 is an equidigital number, since it uses as much as digits as its factorization.
80401943597111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 53.
The spelling of 80401943597111 in words is "eighty trillion, four hundred one billion, nine hundred forty-three million, five hundred ninety-seven thousand, one hundred eleven".
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