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80402347350113 is a prime number
BaseRepresentation
bin10010010010000000100001…
…010110100101100001100001
3101112200101111211101010121212
4102102000201112211201201
541014303001410200423
6443000154540355505
722635610056142565
oct2222004126454141
9345611454333555
1080402347350113
1123689497aa3408
12902661b545b95
1335b2ba78b3909
1415bd6cc7cd6a5
159466b2458578
hex4920215a5861

80402347350113 has 2 divisors, whose sum is σ = 80402347350114. Its totient is φ = 80402347350112.

The previous prime is 80402347349981. The next prime is 80402347350121. The reversal of 80402347350113 is 31105374320408.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63182976307984 + 17219371042129 = 7948772^2 + 4149623^2 .

It is a cyclic number.

It is not a de Polignac number, because 80402347350113 - 210 = 80402347349089 is a prime.

It is a super-2 number, since 2×804023473501132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (80402347350163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40201173675056 + 40201173675057.

It is an arithmetic number, because the mean of its divisors is an integer number (40201173675057).

Almost surely, 280402347350113 is an apocalyptic number.

It is an amenable number.

80402347350113 is a deficient number, since it is larger than the sum of its proper divisors (1).

80402347350113 is an equidigital number, since it uses as much as digits as its factorization.

80402347350113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 41.

The spelling of 80402347350113 in words is "eighty trillion, four hundred two billion, three hundred forty-seven million, three hundred fifty thousand, one hundred thirteen".