Base | Representation |
---|---|
bin | 111010100000100100011… |
… | …1111010011101100011111 |
3 | 1001110202021020001122220011 |
4 | 1311001020333103230133 |
5 | 2023222243223132112 |
6 | 25034100353104051 |
7 | 1456654320355123 |
oct | 165011077235437 |
9 | 31422236048804 |
10 | 8041403333407 |
11 | 26203815a7454 |
12 | a9a589858027 |
13 | 4643bb621502 |
14 | 1db2c5389583 |
15 | de296c4eaa7 |
hex | 75048fd3b1f |
8041403333407 has 2 divisors, whose sum is σ = 8041403333408. Its totient is φ = 8041403333406.
The previous prime is 8041403333363. The next prime is 8041403333419. The reversal of 8041403333407 is 7043333041408.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 8041403333407 - 227 = 8041269115679 is a prime.
It is a super-2 number, since 2×80414033334072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 8041403333407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8041403333437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4020701666703 + 4020701666704.
It is an arithmetic number, because the mean of its divisors is an integer number (4020701666704).
Almost surely, 28041403333407 is an apocalyptic number.
8041403333407 is a deficient number, since it is larger than the sum of its proper divisors (1).
8041403333407 is an equidigital number, since it uses as much as digits as its factorization.
8041403333407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 40.
The spelling of 8041403333407 in words is "eight trillion, forty-one billion, four hundred three million, three hundred thirty-three thousand, four hundred seven".
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