Base | Representation |
---|---|
bin | 10010010010110100011010… |
… | …101011000111011000010011 |
3 | 101112212201100020010020021200 |
4 | 102102310122223013120103 |
5 | 41021211111341203003 |
6 | 443041532123322243 |
7 | 22642621655542254 |
oct | 2222643253073023 |
9 | 345781306106250 |
10 | 80458069866003 |
11 | 237000919a1335 |
12 | 9035390980383 |
13 | 35b82180a5bcb |
14 | 15c229713ab2b |
15 | 947d743c36a3 |
hex | 492d1aac7613 |
80458069866003 has 12 divisors (see below), whose sum is σ = 116382999786768. Its totient is φ = 53562195817200.
The previous prime is 80458069865983. The next prime is 80458069866047. The reversal of 80458069866003 is 30066896085408.
It is not a de Polignac number, because 80458069866003 - 212 = 80458069861907 is a prime.
It is a Smith number, since the sum of its digits (63) coincides with the sum of the digits of its prime factors.
It is not an unprimeable number, because it can be changed into a prime (80458069866103) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6376445575 + ... + 6376458192.
It is an arithmetic number, because the mean of its divisors is an integer number (9698583315564).
Almost surely, 280458069866003 is an apocalyptic number.
80458069866003 is a deficient number, since it is larger than the sum of its proper divisors (35924929920765).
80458069866003 is a wasteful number, since it uses less digits than its factorization.
80458069866003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12752904474 (or 12752904471 counting only the distinct ones).
The product of its (nonzero) digits is 59719680, while the sum is 63.
The spelling of 80458069866003 in words is "eighty trillion, four hundred fifty-eight billion, sixty-nine million, eight hundred sixty-six thousand, three".
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