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80477403497 is a prime number
BaseRepresentation
bin100101011110011010…
…0111011100101101001
321200201121102200110222
41022330310323211221
52304304203402442
6100545410015425
75546206433351
oct1127464734551
9250647380428
1080477403497
113114843a427
121371b877575
1377870079aa
143c7632bb61
1521603718d2
hex12bcd3b969

80477403497 has 2 divisors, whose sum is σ = 80477403498. Its totient is φ = 80477403496.

The previous prime is 80477403473. The next prime is 80477403499. The reversal of 80477403497 is 79430477408.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70036446736 + 10440956761 = 264644^2 + 102181^2 .

It is a cyclic number.

It is not a de Polignac number, because 80477403497 - 220 = 80476354921 is a prime.

It is a super-2 number, since 2×804774034972 (a number of 23 digits) contains 22 as substring.

Together with 80477403499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (80477403499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40238701748 + 40238701749.

It is an arithmetic number, because the mean of its divisors is an integer number (40238701749).

Almost surely, 280477403497 is an apocalyptic number.

It is an amenable number.

80477403497 is a deficient number, since it is larger than the sum of its proper divisors (1).

80477403497 is an equidigital number, since it uses as much as digits as its factorization.

80477403497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4741632, while the sum is 53.

The spelling of 80477403497 in words is "eighty billion, four hundred seventy-seven million, four hundred three thousand, four hundred ninety-seven".