Base | Representation |
---|---|
bin | 1110111111100100… |
… | …11001010001010101 |
3 | 202202222112211020221 |
4 | 13133302121101111 |
5 | 112441132402143 |
6 | 3410424354341 |
7 | 403321411534 |
oct | 73762312125 |
9 | 22688484227 |
10 | 8049497173 |
11 | 3460805403 |
12 | 16879159b1 |
13 | 9b38836a3 |
14 | 5650b031b |
15 | 321a262ed |
hex | 1dfc99455 |
8049497173 has 2 divisors, whose sum is σ = 8049497174. Its totient is φ = 8049497172.
The previous prime is 8049497153. The next prime is 8049497177. The reversal of 8049497173 is 3717949408.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6762266289 + 1287230884 = 82233^2 + 35878^2 .
It is a cyclic number.
It is not a de Polignac number, because 8049497173 - 225 = 8015942741 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 8049497173.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8049497177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4024748586 + 4024748587.
It is an arithmetic number, because the mean of its divisors is an integer number (4024748587).
Almost surely, 28049497173 is an apocalyptic number.
It is an amenable number.
8049497173 is a deficient number, since it is larger than the sum of its proper divisors (1).
8049497173 is an equidigital number, since it uses as much as digits as its factorization.
8049497173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1524096, while the sum is 52.
The square root of 8049497173 is about 89718.9900355549. The cubic root of 8049497173 is about 2004.1162866964.
The spelling of 8049497173 in words is "eight billion, forty-nine million, four hundred ninety-seven thousand, one hundred seventy-three".
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