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80495909803 = 531518790751
BaseRepresentation
bin100101011110111101…
…1100001101110101011
321200202220020220100201
41022331323201232223
52304323423103203
6100551310413031
75546522641531
oct1127573415653
9250686226321
1080495909803
113115792a4a1
1213725b01177
13778aab727a
143c78988151
152161cc9e1d
hex12bdee1bab

80495909803 has 4 divisors (see below), whose sum is σ = 82014700608. Its totient is φ = 78977119000.

The previous prime is 80495909801. The next prime is 80495909869. The reversal of 80495909803 is 30890959408.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 80495909803 - 21 = 80495909801 is a prime.

It is a super-2 number, since 2×804959098032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (80495909801) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 759395323 + ... + 759395428.

It is an arithmetic number, because the mean of its divisors is an integer number (20503675152).

Almost surely, 280495909803 is an apocalyptic number.

80495909803 is a deficient number, since it is larger than the sum of its proper divisors (1518790805).

80495909803 is a wasteful number, since it uses less digits than its factorization.

80495909803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1518790804.

The product of its (nonzero) digits is 2799360, while the sum is 55.

The spelling of 80495909803 in words is "eighty billion, four hundred ninety-five million, nine hundred nine thousand, eight hundred three".

Divisors: 1 53 1518790751 80495909803