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80623417451 is a prime number
BaseRepresentation
bin100101100010110000…
…1111011100001101011
321201002210011221222012
41023011201323201223
52310104043324301
6101012103350135
75552631512123
oct1130541734153
9251083157865
1080623417451
11312128a9915
121376075234b
1377ab33c495
143c8b899c83
15216d0b4ebb
hex12c587b86b

80623417451 has 2 divisors, whose sum is σ = 80623417452. Its totient is φ = 80623417450.

The previous prime is 80623417423. The next prime is 80623417453. The reversal of 80623417451 is 15471432608.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 80623417451 - 218 = 80623155307 is a prime.

It is a super-2 number, since 2×806234174512 (a number of 23 digits) contains 22 as substring.

Together with 80623417453, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 80623417399 and 80623417408.

It is not a weakly prime, because it can be changed into another prime (80623417453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40311708725 + 40311708726.

It is an arithmetic number, because the mean of its divisors is an integer number (40311708726).

Almost surely, 280623417451 is an apocalyptic number.

80623417451 is a deficient number, since it is larger than the sum of its proper divisors (1).

80623417451 is an equidigital number, since it uses as much as digits as its factorization.

80623417451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 41.

The spelling of 80623417451 in words is "eighty billion, six hundred twenty-three million, four hundred seventeen thousand, four hundred fifty-one".