Base | Representation |
---|---|
bin | 10111011110100111011… |
… | …11011100000000111011 |
3 | 2212010021002122201220011 |
4 | 23233103233130000323 |
5 | 101204121043444233 |
6 | 1414333103042351 |
7 | 112166026005421 |
oct | 13572357340073 |
9 | 2763232581804 |
10 | 806711312443 |
11 | 291140561103 |
12 | 110419ba03b7 |
13 | 5b0c351587a |
14 | 2b08b815111 |
15 | 15eb75d40cd |
hex | bbd3bdc03b |
806711312443 has 2 divisors, whose sum is σ = 806711312444. Its totient is φ = 806711312442.
The previous prime is 806711312441. The next prime is 806711312501. The reversal of 806711312443 is 344213117608.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 806711312443 - 21 = 806711312441 is a prime.
Together with 806711312441, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 806711312396 and 806711312405.
It is not a weakly prime, because it can be changed into another prime (806711312441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 403355656221 + 403355656222.
It is an arithmetic number, because the mean of its divisors is an integer number (403355656222).
Almost surely, 2806711312443 is an apocalyptic number.
806711312443 is a deficient number, since it is larger than the sum of its proper divisors (1).
806711312443 is an equidigital number, since it uses as much as digits as its factorization.
806711312443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 806711312443 in words is "eight hundred six billion, seven hundred eleven million, three hundred twelve thousand, four hundred forty-three".
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