Base | Representation |
---|---|
bin | 100101101000000010… |
… | …1000101010100111001 |
3 | 21201120010012211221221 |
4 | 1023100011011110321 |
5 | 2310434400423133 |
6 | 101041425032041 |
7 | 5560211052163 |
oct | 1132005052471 |
9 | 251503184857 |
10 | 80800404793 |
11 | 312a37a4049 |
12 | 137aba85621 |
13 | 7808bca014 |
14 | 3ca71ab933 |
15 | 217d8c5a2d |
hex | 12d0145539 |
80800404793 has 2 divisors, whose sum is σ = 80800404794. Its totient is φ = 80800404792.
The previous prime is 80800404791. The next prime is 80800404823. The reversal of 80800404793 is 39740400808.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46689269929 + 34111134864 = 216077^2 + 184692^2 .
It is a cyclic number.
It is not a de Polignac number, because 80800404793 - 21 = 80800404791 is a prime.
Together with 80800404791, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (80800404791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40400202396 + 40400202397.
It is an arithmetic number, because the mean of its divisors is an integer number (40400202397).
Almost surely, 280800404793 is an apocalyptic number.
It is an amenable number.
80800404793 is a deficient number, since it is larger than the sum of its proper divisors (1).
80800404793 is an equidigital number, since it uses as much as digits as its factorization.
80800404793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 193536, while the sum is 43.
The spelling of 80800404793 in words is "eighty billion, eight hundred million, four hundred four thousand, seven hundred ninety-three".
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