Base | Representation |
---|---|
bin | 10111100100101111100… |
… | …00110010010000010111 |
3 | 2212102202021220101010212 |
4 | 23302113300302100113 |
5 | 101232340000000043 |
6 | 1420035303040035 |
7 | 112343361254024 |
oct | 13622760622027 |
9 | 2772667811125 |
10 | 810000000023 |
11 | 292578979825 |
12 | 110b9744001b |
13 | 5b4c8966b56 |
14 | 2b2c04c854b |
15 | 1610b1a0018 |
hex | bc97c32417 |
810000000023 has 2 divisors, whose sum is σ = 810000000024. Its totient is φ = 810000000022.
The previous prime is 809999999959. The next prime is 810000000053. The reversal of 810000000023 is 320000000018.
810000000023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 810000000023 - 26 = 809999999959 is a prime.
It is a super-2 number, since 2×8100000000232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 809999999935 and 810000000007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (810000000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405000000011 + 405000000012.
It is an arithmetic number, because the mean of its divisors is an integer number (405000000012).
Almost surely, 2810000000023 is an apocalyptic number.
810000000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
810000000023 is an equidigital number, since it uses as much as digits as its factorization.
810000000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
The spelling of 810000000023 in words is "eight hundred ten billion, twenty-three", and thus it is an aban number.
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