810000019 has 2 divisors, whose sum is σ = 810000020. Its totient is φ = 810000018.

The previous prime is 810000011. The next prime is 810000049. The reversal of 810000019 is 910000018.

810000019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 810000019 - 2³ = 810000011 is a prime.

It is a super-2 number, since 2×810000019² = 1312200061560000722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 809999960 and 810000005.

It is not a weakly prime, because it can be changed into another prime (810000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405000009 + 405000010.

It is an arithmetic number, because the mean of its divisors is an integer number (405000010).

Almost surely, 2^810000019 is an apocalyptic number.

810000019 is a deficient number, since it is larger than the sum of its proper divisors (1).

810000019 is an equidigital number, since it uses as much as digits as its factorization.

810000019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 19.

The square root of 810000019 is about 28460.4992753114. The cubic root of 810000019 is about 932.1697590747.

Subtracting 810000019 from its reverse (910000018), we obtain a palindrome (99999999).

The spelling of 810000019 in words is "eight hundred ten million, nineteen", and thus it is an aban number.