810104964503 has 2 divisors, whose sum is σ = 810104964504. Its totient is φ = 810104964502.

The previous prime is 810104964443. The next prime is 810104964523. The reversal of 810104964503 is 305469401018.

810104964503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-810104964503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (810104964523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405052482251 + 405052482252.

It is an arithmetic number, because the mean of its divisors is an integer number (405052482252).

Almost surely, 2^810104964503 is an apocalyptic number.

810104964503 is a deficient number, since it is larger than the sum of its proper divisors (1).

810104964503 is an equidigital number, since it uses as much as digits as its factorization.

810104964503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 41.

The spelling of 810104964503 in words is "eight hundred ten billion, one hundred four million, nine hundred sixty-four thousand, five hundred three".