Base | Representation |
---|---|
bin | 1111000110011101… |
… | …00101000011011001 |
3 | 202221000011022010111 |
4 | 13203032211003121 |
5 | 113100421421423 |
6 | 3420245444321 |
7 | 404622131332 |
oct | 74316450331 |
9 | 22830138114 |
10 | 8107217113 |
11 | 3490349236 |
12 | 16a31106a1 |
13 | 9c28128b8 |
14 | 56ca17289 |
15 | 326b2860d |
hex | 1e33a50d9 |
8107217113 has 2 divisors, whose sum is σ = 8107217114. Its totient is φ = 8107217112.
The previous prime is 8107217071. The next prime is 8107217143. The reversal of 8107217113 is 3117127018.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4323983049 + 3783234064 = 65757^2 + 61508^2 .
It is a cyclic number.
It is not a de Polignac number, because 8107217113 - 221 = 8105119961 is a prime.
It is not a weakly prime, because it can be changed into another prime (8107217143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4053608556 + 4053608557.
It is an arithmetic number, because the mean of its divisors is an integer number (4053608557).
Almost surely, 28107217113 is an apocalyptic number.
It is an amenable number.
8107217113 is a deficient number, since it is larger than the sum of its proper divisors (1).
8107217113 is an equidigital number, since it uses as much as digits as its factorization.
8107217113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2352, while the sum is 31.
The square root of 8107217113 is about 90040.0861450054. The cubic root of 8107217113 is about 2008.8951390164.
The spelling of 8107217113 in words is "eight billion, one hundred seven million, two hundred seventeen thousand, one hundred thirteen".
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