Base | Representation |
---|---|
bin | 100101110001010001… |
… | …1111001110100010001 |
3 | 21202100201122222221200 |
4 | 1023202203321310101 |
5 | 2312103240132001 |
6 | 101132302541413 |
7 | 5600664440064 |
oct | 1134243716421 |
9 | 252321588850 |
10 | 81110474001 |
11 | 31442825697 |
12 | 13877897869 |
13 | 785821201b |
14 | 3cd64428db |
15 | 219ac23086 |
hex | 12e28f9d11 |
81110474001 has 48 divisors (see below), whose sum is σ = 128573874000. Its totient is φ = 49062703104.
The previous prime is 81110473957. The next prime is 81110474017. The reversal of 81110474001 is 10047401118.
81110474001 is a `hidden beast` number, since 81 + 110 + 474 + 0 + 0 + 1 = 666.
It can be written as a sum of positive squares in 8 ways, for example, as 37713251601 + 43397222400 = 194199^2 + 208320^2 .
It is a de Polignac number, because none of the positive numbers 2k-81110474001 is a prime.
It is a super-3 number, since 3×811104740013 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (81110434001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 551325 + ... + 682773.
It is an arithmetic number, because the mean of its divisors is an integer number (2678622375).
Almost surely, 281110474001 is an apocalyptic number.
It is an amenable number.
81110474001 is a deficient number, since it is larger than the sum of its proper divisors (47463399999).
81110474001 is a wasteful number, since it uses less digits than its factorization.
81110474001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131618 (or 131615 counting only the distinct ones).
The product of its (nonzero) digits is 896, while the sum is 27.
Adding to 81110474001 its reverse (10047401118), we get a palindrome (91157875119).
The spelling of 81110474001 in words is "eighty-one billion, one hundred ten million, four hundred seventy-four thousand, one".
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