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81110434001 is a prime number
BaseRepresentation
bin100101110001010001…
…1110000000011010001
321202100201120222002012
41023202203300003101
52312103232342001
6101132302032305
75600664212342
oct1134243600321
9252321528065
1081110434001
11314427a8633
1213877878695
1378581c9a5c
143cd64320c9
15219ac162bb
hex12e28f00d1

81110434001 has 2 divisors, whose sum is σ = 81110434002. Its totient is φ = 81110434000.

The previous prime is 81110433953. The next prime is 81110434037. The reversal of 81110434001 is 10043401118.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48213180625 + 32897253376 = 219575^2 + 181376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-81110434001 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (81110430001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40555217000 + 40555217001.

It is an arithmetic number, because the mean of its divisors is an integer number (40555217001).

Almost surely, 281110434001 is an apocalyptic number.

It is an amenable number.

81110434001 is a deficient number, since it is larger than the sum of its proper divisors (1).

81110434001 is an equidigital number, since it uses as much as digits as its factorization.

81110434001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 81110434001 its reverse (10043401118), we get a palindrome (91153835119).

The spelling of 81110434001 in words is "eighty-one billion, one hundred ten million, four hundred thirty-four thousand, one".