81113119 has 2 divisors, whose sum is σ = 81113120. Its totient is φ = 81113118.

The previous prime is 81113101. The next prime is 81113183. The reversal of 81113119 is 91131118.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-81113119 is a prime.

It is a super-2 number, since 2×81113119² = 13158676147816322, which contains 22 as substring.

It is equal to p_4730731 and since 81113119 and 4730731 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 81113093 and 81113102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (81113719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40556559 + 40556560.

It is an arithmetic number, because the mean of its divisors is an integer number (40556560).

Almost surely, 2^81113119 is an apocalyptic number.

81113119 is a deficient number, since it is larger than the sum of its proper divisors (1).

81113119 is an equidigital number, since it uses as much as digits as its factorization.

81113119 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 25.

The square root of 81113119 is about 9006.2821963338. The cubic root of 81113119 is about 432.8761920082.

The spelling of 81113119 in words is "eighty-one million, one hundred thirteen thousand, one hundred nineteen".