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8113325443 is a prime number
BaseRepresentation
bin1111000111001011…
…11000010110000011
3202221102122122011221
413203211320112003
5113104002403233
63421024415511
7405025062016
oct74345702603
922842578157
108113325443
113493840543
1216a5177597
139c3b70cb2
1456d76737d
1532743342d
hex1e3978583

8113325443 has 2 divisors, whose sum is σ = 8113325444. Its totient is φ = 8113325442.

The previous prime is 8113325411. The next prime is 8113325449. The reversal of 8113325443 is 3445233118.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 8113325443 - 25 = 8113325411 is a prime.

It is a super-2 number, since 2×81133254432 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 8113325399 and 8113325408.

It is not a weakly prime, because it can be changed into another prime (8113325449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4056662721 + 4056662722.

It is an arithmetic number, because the mean of its divisors is an integer number (4056662722).

Almost surely, 28113325443 is an apocalyptic number.

8113325443 is a deficient number, since it is larger than the sum of its proper divisors (1).

8113325443 is an equidigital number, since it uses as much as digits as its factorization.

8113325443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 34.

The square root of 8113325443 is about 90073.9998168173. Note that the first 3 decimals coincide. The cubic root of 8113325443 is about 2009.3995420164.

The spelling of 8113325443 in words is "eight billion, one hundred thirteen million, three hundred twenty-five thousand, four hundred forty-three".