Base | Representation |
---|---|
bin | 111011000011000010011… |
… | …1010010000000010011001 |
3 | 1001201211022210021121220011 |
4 | 1312012010322100002121 |
5 | 2030430341302202242 |
6 | 25132101321201521 |
7 | 1465214515023235 |
oct | 166060472200231 |
9 | 31654283247804 |
10 | 8115423084697 |
11 | 2649805843125 |
12 | ab09a69302a1 |
13 | 46b3867b4706 |
14 | 200b07bb75c5 |
15 | e117a1d7d17 |
hex | 76184e90099 |
8115423084697 has 2 divisors, whose sum is σ = 8115423084698. Its totient is φ = 8115423084696.
The previous prime is 8115423084661. The next prime is 8115423084701. The reversal of 8115423084697 is 7964803245118.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5390889905241 + 2724533179456 = 2321829^2 + 1650616^2 .
It is a cyclic number.
It is not a de Polignac number, because 8115423084697 - 27 = 8115423084569 is a prime.
It is not a weakly prime, because it can be changed into another prime (8115423084997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4057711542348 + 4057711542349.
It is an arithmetic number, because the mean of its divisors is an integer number (4057711542349).
It is a 1-persistent number, because it is pandigital, but 2⋅8115423084697 = 16230846169394 is not.
Almost surely, 28115423084697 is an apocalyptic number.
It is an amenable number.
8115423084697 is a deficient number, since it is larger than the sum of its proper divisors (1).
8115423084697 is an equidigital number, since it uses as much as digits as its factorization.
8115423084697 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 58.
The spelling of 8115423084697 in words is "eight trillion, one hundred fifteen billion, four hundred twenty-three million, eighty-four thousand, six hundred ninety-seven".
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