Base | Representation |
---|---|
bin | 100101110011001000… |
… | …0011100100111000111 |
3 | 21202112001100100121212 |
4 | 1023212100130213013 |
5 | 2312220123420003 |
6 | 101142400002035 |
7 | 5602346500640 |
oct | 1134620344707 |
9 | 252461310555 |
10 | 81172482503 |
11 | 31474828592 |
12 | 1389460031b |
13 | 7868013248 |
14 | 3d007846c7 |
15 | 21a13c0dd8 |
hex | 12e641c9c7 |
81172482503 has 4 divisors (see below), whose sum is σ = 92768551440. Its totient is φ = 69576413568.
The previous prime is 81172482497. The next prime is 81172482529. The reversal of 81172482503 is 30528427118.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 81172482503 - 28 = 81172482247 is a prime.
It is a super-2 number, since 2×811724825032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (81172482553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5798034458 + ... + 5798034471.
It is an arithmetic number, because the mean of its divisors is an integer number (23192137860).
Almost surely, 281172482503 is an apocalyptic number.
81172482503 is a deficient number, since it is larger than the sum of its proper divisors (11596068937).
81172482503 is a wasteful number, since it uses less digits than its factorization.
81172482503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11596068936.
The product of its (nonzero) digits is 107520, while the sum is 41.
The spelling of 81172482503 in words is "eighty-one billion, one hundred seventy-two million, four hundred eighty-two thousand, five hundred three".
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