Base | Representation |
---|---|
bin | 100101110011110011… |
… | …1101110100110010000 |
3 | 21202120122101210100201 |
4 | 1023213213232212100 |
5 | 2312242003101304 |
6 | 101144534224544 |
7 | 5603045124031 |
oct | 1134747564620 |
9 | 252518353321 |
10 | 81195362704 |
11 | 31486735845 |
12 | 138a01b5154 |
13 | 786c994621 |
14 | 3d0381ca88 |
15 | 21a33e03a4 |
hex | 12e79ee990 |
81195362704 has 15 divisors (see below), whose sum is σ = 157318223617. Its totient is φ = 40597111456.
The previous prime is 81195362683. The next prime is 81195362711. The reversal of 81195362704 is 40726359118.
The square root of 81195362704 is 284948.
It is a perfect power (a square), and thus also a powerful number.
It can be written as a sum of positive squares in only one way, i.e., 4160250000 + 77035112704 = 64500^2 + 277552^2 .
It is a super-2 number, since 2×811953627042 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 1104174 + ... + 1175410.
It is a 2-persistent number, because it is pandigital, and so is 2⋅81195362704 = 162390725408, but 3⋅81195362704 = 243586088112 is not.
Almost surely, 281195362704 is an apocalyptic number.
81195362704 is the 284948-th square number.
It is an amenable number.
81195362704 is a deficient number, since it is larger than the sum of its proper divisors (76122860913).
81195362704 is an frugal number, since it uses more digits than its factorization.
81195362704 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142482 (or 71239 counting only the distinct ones).
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 81195362704 in words is "eighty-one billion, one hundred ninety-five million, three hundred sixty-two thousand, seven hundred four".
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