Base | Representation |
---|---|
bin | 1001101011100… |
… | …00010011011111 |
3 | 12122210101221102 |
4 | 10311300103133 |
5 | 131241402401 |
6 | 12020223315 |
7 | 2004122501 |
oct | 465602337 |
9 | 178711842 |
10 | 81200351 |
11 | 41921031 |
12 | 2323ab3b |
13 | 13a9085b |
14 | aad9d71 |
15 | 71de56b |
hex | 4d704df |
81200351 has 2 divisors, whose sum is σ = 81200352. Its totient is φ = 81200350.
The previous prime is 81200291. The next prime is 81200363. The reversal of 81200351 is 15300218.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-81200351 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (81203351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40600175 + 40600176.
It is an arithmetic number, because the mean of its divisors is an integer number (40600176).
Almost surely, 281200351 is an apocalyptic number.
81200351 is a deficient number, since it is larger than the sum of its proper divisors (1).
81200351 is an equidigital number, since it uses as much as digits as its factorization.
81200351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 81200351 is about 9011.1237368044. The cubic root of 81200351 is about 433.0313133504.
Adding to 81200351 its reverse (15300218), we get a palindrome (96500569).
The spelling of 81200351 in words is "eighty-one million, two hundred thousand, three hundred fifty-one".
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