812016493 has 4 divisors (see below), whose sum is σ = 814229440. Its totient is φ = 809803548.

The previous prime is 812016479. The next prime is 812016503. The reversal of 812016493 is 394610218.

812016493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 812016493 - 2⁵ = 812016461 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (812016893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1105923 + ... + 1106656.

It is an arithmetic number, because the mean of its divisors is an integer number (203557360).

Almost surely, 2^812016493 is an apocalyptic number.

It is an amenable number.

812016493 is a deficient number, since it is larger than the sum of its proper divisors (2212947).

812016493 is a wasteful number, since it uses less digits than its factorization.

812016493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2212946.

The product of its (nonzero) digits is 10368, while the sum is 34.

The square root of 812016493 is about 28495.9030914972. The cubic root of 812016493 is about 932.9426555250.

The spelling of 812016493 in words is "eight hundred twelve million, sixteen thousand, four hundred ninety-three".