Base | Representation |
---|---|
bin | 10111101001000001000… |
… | …00110110010010000011 |
3 | 2212122200012000221010211 |
4 | 23310200200312102003 |
5 | 101302034320111203 |
6 | 1421055101534551 |
7 | 112454260430416 |
oct | 13644040662203 |
9 | 2778605027124 |
10 | 812294300803 |
11 | 293545a57977 |
12 | 111517874457 |
13 | 5b7a3094b8b |
14 | 2b45b0b1b7d |
15 | 161e27e7c6d |
hex | bd20836483 |
812294300803 has 2 divisors, whose sum is σ = 812294300804. Its totient is φ = 812294300802.
The previous prime is 812294300801. The next prime is 812294300821. The reversal of 812294300803 is 308003492218.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 812294300803 - 21 = 812294300801 is a prime.
It is a super-2 number, since 2×8122943008032 (a number of 25 digits) contains 22 as substring.
Together with 812294300801, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (812294300801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406147150401 + 406147150402.
It is an arithmetic number, because the mean of its divisors is an integer number (406147150402).
Almost surely, 2812294300803 is an apocalyptic number.
812294300803 is a deficient number, since it is larger than the sum of its proper divisors (1).
812294300803 is an equidigital number, since it uses as much as digits as its factorization.
812294300803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 40.
The spelling of 812294300803 in words is "eight hundred twelve billion, two hundred ninety-four million, three hundred thousand, eight hundred three".
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