Base | Representation |
---|---|
bin | 10111101010100100000… |
… | …10101111011110011011 |
3 | 2212201211002122111202122 |
4 | 23311102002233132123 |
5 | 101310240032110103 |
6 | 1421313344251455 |
7 | 112514000515406 |
oct | 13652202573633 |
9 | 2781732574678 |
10 | 813125269403 |
11 | 29393201a987 |
12 | 11170a010b8b |
13 | 5b8a629b885 |
14 | 2b4d95bcd3d |
15 | 1624073ab38 |
hex | bd520af79b |
813125269403 has 2 divisors, whose sum is σ = 813125269404. Its totient is φ = 813125269402.
The previous prime is 813125269387. The next prime is 813125269459. The reversal of 813125269403 is 304962521318.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 813125269403 - 24 = 813125269387 is a prime.
It is a super-2 number, since 2×8131252694032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (813125269703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406562634701 + 406562634702.
It is an arithmetic number, because the mean of its divisors is an integer number (406562634702).
Almost surely, 2813125269403 is an apocalyptic number.
813125269403 is a deficient number, since it is larger than the sum of its proper divisors (1).
813125269403 is an equidigital number, since it uses as much as digits as its factorization.
813125269403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 44.
The spelling of 813125269403 in words is "eight hundred thirteen billion, one hundred twenty-five million, two hundred sixty-nine thousand, four hundred three".
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