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813928627957 is a prime number
BaseRepresentation
bin10111101100000011110…
…11010011111011110101
32212210220002022100112011
423312001323103323311
5101313411212043312
61421525203124221
7112542624120544
oct13660173237365
92783802270464
10813928627957
11294204545075
121118b3073671
135b9a3859373
142b57418015b
151628b027da7
hexbd81ed3ef5

813928627957 has 2 divisors, whose sum is σ = 813928627958. Its totient is φ = 813928627956.

The previous prime is 813928627891. The next prime is 813928627969. The reversal of 813928627957 is 759726829318.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 557121916836 + 256806711121 = 746406^2 + 506761^2 .

It is a cyclic number.

It is not a de Polignac number, because 813928627957 - 215 = 813928595189 is a prime.

It is a super-2 number, since 2×8139286279572 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 813928627892 and 813928627901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (813928637957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406964313978 + 406964313979.

It is an arithmetic number, because the mean of its divisors is an integer number (406964313979).

Almost surely, 2813928627957 is an apocalyptic number.

It is an amenable number.

813928627957 is a deficient number, since it is larger than the sum of its proper divisors (1).

813928627957 is an equidigital number, since it uses as much as digits as its factorization.

813928627957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 91445760, while the sum is 67.

The spelling of 813928627957 in words is "eight hundred thirteen billion, nine hundred twenty-eight million, six hundred twenty-seven thousand, nine hundred fifty-seven".