8143811343313 has 2 divisors, whose sum is σ = 8143811343314. Its totient is φ = 8143811343312.

The previous prime is 8143811343307. The next prime is 8143811343361. The reversal of 8143811343313 is 3133431183418.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7236654150609 + 907157192704 = 2690103^2 + 952448^2 .

It is a cyclic number.

It is not a de Polignac number, because 8143811343313 - 2⁹ = 8143811342801 is a prime.

It is a super-3 number, since 3×8143811343313³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 8143811343313.

It is not a weakly prime, because it can be changed into another prime (8143811346313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4071905671656 + 4071905671657.

It is an arithmetic number, because the mean of its divisors is an integer number (4071905671657).

Almost surely, 2^{8143811343313} is an apocalyptic number.

It is an amenable number.

8143811343313 is a deficient number, since it is larger than the sum of its proper divisors (1).

8143811343313 is an equidigital number, since it uses as much as digits as its factorization.

8143811343313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 43.

The spelling of 8143811343313 in words is "eight trillion, one hundred forty-three billion, eight hundred eleven million, three hundred forty-three thousand, three hundred thirteen".