Base | Representation |
---|---|
bin | 1111001010110110… |
… | …00110110000001011 |
3 | 210000120110212122001 |
4 | 13211123012300023 |
5 | 113134334232212 |
6 | 3424043211431 |
7 | 405550220323 |
oct | 74533066013 |
9 | 23016425561 |
10 | 8144055307 |
11 | 34aa11a323 |
12 | 16b3516b77 |
13 | 9ca34024b |
14 | 573886283 |
15 | 329ea3657 |
hex | 1e56c6c0b |
8144055307 has 4 divisors (see below), whose sum is σ = 8144365320. Its totient is φ = 8143745296.
The previous prime is 8144055277. The next prime is 8144055319. The reversal of 8144055307 is 7035504418.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8144055307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (8144055347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111538 + ... + 169495.
It is an arithmetic number, because the mean of its divisors is an integer number (2036091330).
Almost surely, 28144055307 is an apocalyptic number.
8144055307 is a deficient number, since it is larger than the sum of its proper divisors (310013).
8144055307 is a wasteful number, since it uses less digits than its factorization.
8144055307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 310012.
The product of its (nonzero) digits is 67200, while the sum is 37.
The square root of 8144055307 is about 90244.4198108670. The cubic root of 8144055307 is about 2011.9332658884.
The spelling of 8144055307 in words is "eight billion, one hundred forty-four million, fifty-five thousand, three hundred seven".
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