Base | Representation |
---|---|
bin | 100110000100000011… |
… | …1110101111100011111 |
3 | 21210222122110101002101 |
4 | 1030020013311330133 |
5 | 2314401101333234 |
6 | 101315013505531 |
7 | 5622416036464 |
oct | 1141007657437 |
9 | 253878411071 |
10 | 81740652319 |
11 | 31736515a17 |
12 | 13a129422a7 |
13 | 7928945ac1 |
14 | 3d5600366b |
15 | 21d6202814 |
hex | 13081f5f1f |
81740652319 has 2 divisors, whose sum is σ = 81740652320. Its totient is φ = 81740652318.
The previous prime is 81740652313. The next prime is 81740652403. The reversal of 81740652319 is 91325604718.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-81740652319 is a prime.
It is a super-2 number, since 2×817406523192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (81740652313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40870326159 + 40870326160.
It is an arithmetic number, because the mean of its divisors is an integer number (40870326160).
It is a 1-persistent number, because it is pandigital, but 2⋅81740652319 = 163481304638 is not.
Almost surely, 281740652319 is an apocalyptic number.
81740652319 is a deficient number, since it is larger than the sum of its proper divisors (1).
81740652319 is an equidigital number, since it uses as much as digits as its factorization.
81740652319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 81740652319 in words is "eighty-one billion, seven hundred forty million, six hundred fifty-two thousand, three hundred nineteen".
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