Base | Representation |
---|---|
bin | 10010101101110111010011… |
… | …111010100110111011001111 |
3 | 101210110101112122012101000101 |
4 | 102231313103322212323033 |
5 | 41242133401004143312 |
6 | 451023420423111531 |
7 | 23224115113516066 |
oct | 2255672372467317 |
9 | 353411478171011 |
10 | 82316603584207 |
11 | 24257303808843 |
12 | 9295613ba25a7 |
13 | 36c1565060515 |
14 | 16482057551dd |
15 | 97b39ca95a57 |
hex | 4addd3ea6ecf |
82316603584207 has 4 divisors (see below), whose sum is σ = 82316884678600. Its totient is φ = 82316322489816.
The previous prime is 82316603584151. The next prime is 82316603584219. The reversal of 82316603584207 is 70248530661328.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 82316603584207 - 211 = 82316603582159 is a prime.
It is a super-3 number, since 3×823166035842073 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (82316603584247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140107473 + ... + 140693770.
It is an arithmetic number, because the mean of its divisors is an integer number (20579221169650).
Almost surely, 282316603584207 is an apocalyptic number.
82316603584207 is a deficient number, since it is larger than the sum of its proper divisors (281094393).
82316603584207 is a wasteful number, since it uses less digits than its factorization.
82316603584207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281094392.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 82316603584207 in words is "eighty-two trillion, three hundred sixteen billion, six hundred three million, five hundred eighty-four thousand, two hundred seven".
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