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82715604893 = 372235556889
BaseRepresentation
bin100110100001000111…
…0111111011110011101
321220111121000002120222
41031002032333132131
52323400143324033
6101555442251125
75655525020015
oct1150216773635
9256447002528
1082715604893
1132096891249
1214045356aa5
137a5292330c
1440096b0c45
152241ad7598
hex13423bf79d

82715604893 has 4 divisors (see below), whose sum is σ = 84951161820. Its totient is φ = 80480047968.

The previous prime is 82715604877. The next prime is 82715604901. The reversal of 82715604893 is 39840651728.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 38782606489 + 43932998404 = 196933^2 + 209602^2 .

It is a cyclic number.

It is not a de Polignac number, because 82715604893 - 24 = 82715604877 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (82715604493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117778408 + ... + 1117778481.

It is an arithmetic number, because the mean of its divisors is an integer number (21237790455).

It is a 2-persistent number, because it is pandigital, and so is 2⋅82715604893 = 165431209786, but 3⋅82715604893 = 248146814679 is not.

Almost surely, 282715604893 is an apocalyptic number.

It is an amenable number.

82715604893 is a deficient number, since it is larger than the sum of its proper divisors (2235556927).

82715604893 is a wasteful number, since it uses less digits than its factorization.

82715604893 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2235556926.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 82715604893 in words is "eighty-two billion, seven hundred fifteen million, six hundred four thousand, eight hundred ninety-three".

Divisors: 1 37 2235556889 82715604893