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8271970344853 is a prime number
BaseRepresentation
bin111100001011111011111…
…0110101001111110010101
31002021210101211120102020121
41320113313312221332111
52041011443402013403
625332031332231541
71512426064543435
oct170276766517625
932253354512217
108271970344853
1126aa139678786
12b171b616b5b1
13480074620cb7
14208518d122c5
15e528d9a13bd
hex785f7da9f95

8271970344853 has 2 divisors, whose sum is σ = 8271970344854. Its totient is φ = 8271970344852.

The previous prime is 8271970344797. The next prime is 8271970344877. The reversal of 8271970344853 is 3584430791728.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4510938466609 + 3761031878244 = 2123897^2 + 1939338^2 .

It is a cyclic number.

It is not a de Polignac number, because 8271970344853 - 213 = 8271970336661 is a prime.

It is a super-2 number, since 2×82719703448532 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 8271970344791 and 8271970344800.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8271970344353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4135985172426 + 4135985172427.

It is an arithmetic number, because the mean of its divisors is an integer number (4135985172427).

Almost surely, 28271970344853 is an apocalyptic number.

It is an amenable number.

8271970344853 is a deficient number, since it is larger than the sum of its proper divisors (1).

8271970344853 is an equidigital number, since it uses as much as digits as its factorization.

8271970344853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40642560, while the sum is 61.

The spelling of 8271970344853 in words is "eight trillion, two hundred seventy-one billion, nine hundred seventy million, three hundred forty-four thousand, eight hundred fifty-three".