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83001210249983 is a prime number
BaseRepresentation
bin10010110111110100111001…
…101001110010001011111111
3101212212211122001102100221112
4102313310321221302023333
541334342434310444413
6452310121331552235
723324432236253144
oct2267647151621377
9355784561370845
1083001210249983
11244a0685392613
12938623545b67b
133740c99334b6c
14166d3cc4c83cb
1598e0ba5402a8
hex4b7d39a722ff

83001210249983 has 2 divisors, whose sum is σ = 83001210249984. Its totient is φ = 83001210249982.

The previous prime is 83001210249961. The next prime is 83001210250003. The reversal of 83001210249983 is 38994201210038.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 83001210249983 - 222 = 83001206055679 is a prime.

It is a super-3 number, since 3×830012102499833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83001210249883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41500605124991 + 41500605124992.

It is an arithmetic number, because the mean of its divisors is an integer number (41500605124992).

Almost surely, 283001210249983 is an apocalyptic number.

83001210249983 is a deficient number, since it is larger than the sum of its proper divisors (1).

83001210249983 is an equidigital number, since it uses as much as digits as its factorization.

83001210249983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 746496, while the sum is 50.

The spelling of 83001210249983 in words is "eighty-three trillion, one billion, two hundred ten million, two hundred forty-nine thousand, nine hundred eighty-three".